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By default Perl assumes that it must do most of its arithmetic in floating
point. But by saying
use integer;
you may tell the compiler that it's okay to use integer operations from here to the end of the enclosing
BLOCK. An inner
BLOCK may countermand this by saying
no integer;
which lasts until the end of that
BLOCK.
The bitwise operators (``&'', ``|'', ``^'', ``~'', ``<<``, and ''>>``) always produce integral results. However, use integer still has meaning for them. By default, their results are interpreted as
unsigned integers. However, if use integer is in effect, their results are interpreted as signed integers. For
example, ~0 usually evaluates to a large integral value. However, use integer; ~0 is -1.
Source: Perl operators and precedence
Copyright: Larry Wall, et al. |
Next: Floating-point Arithmetic
Previous: Constant Folding
(Corrections, notes, and links courtesy of RocketAware.com)
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